Hi All,
Kamailio send 2 INVITE(lookup rewrite r-uri and append branch) request for Client behind NAT. Due to this reason for one request,Client respond with 486 Busy here. we only want to send 1 INVITE request.
Following are the AOR for client at kamailio.if field(ip port) in CONTACT and RECEIVED differ then kamailio send 2 INVITE request.
FOLLOWING INVITE HAS BEEN GENERATED AFTER LOOKUP FUNCTION(one from contact and one from Received field).
INVITE:sip:123@192.168.230.124:45672 INVITE:sip:123@204.192.206.208:45672
I want only ONE INVITE request to be generated.Please suggest how do solve this issue or if there is any config change or any code change required to achieve this?
AOR:: 123 Contact:: sip:123@192.168.230.124:45672 Q=1 Expires:: 894 Callid:: 003A8EC4-12351@192.168.230.124 Cseq:: 2 User-agent:: SIPPER for 3CX Phone Received:: sip:204.192.206.208: 45672 State:: CS_NEW Flags:: 0 Cflag:: 192 Socket:: udp:172.12.120.88:5060 Methods:: 4294967295 Ruid:: uloc-5aba112d-7fce-5 Reg-Id:: 0 Last-Keepalive:: 1522144583 Last-Modified:: 1522144583
thanks, amit