Hi All,

Kamailio send 2 INVITE(lookup rewrite r-uri and append branch) request for Client behind NAT.
Due to this reason for one request,Client respond with 486 Busy here. we only want to send  1 INVITE request.

Following are the AOR for client at kamailio.if field(ip port) in CONTACT and RECEIVED differ then kamailio send 2 INVITE request.


FOLLOWING INVITE HAS BEEN GENERATED AFTER LOOKUP FUNCTION(one from contact and one from Received field).

INVITE:sip:123@192.168.230.124:45672
INVITE:sip:123@204.192.206.208:45672

I want only ONE INVITE request to be generated.Please suggest how do solve this issue or if there is any config change or any code change required to achieve this?


  AOR:: 123
                Contact:: sip:123@192.168.230.124:45672 Q=1
                        Expires:: 894
                        Callid:: 003A8EC4-12351@192.168.230.124
                        Cseq:: 2
                        User-agent:: SIPPER for 3CX Phone
                        Received:: sip:204.192.206.208: 45672
                        State:: CS_NEW
                        Flags:: 0
                        Cflag:: 192
                        Socket:: udp:172.12.120.88:5060
                        Methods:: 4294967295
                        Ruid:: uloc-5aba112d-7fce-5
                        Reg-Id:: 0
                        Last-Keepalive:: 1522144583
                        Last-Modified:: 1522144583

thanks,
amit