28 Sep
2004
28 Sep
'04
12:30 p.m.
On Sep 26, 2004 at 14:13, Michael Shuler <mike(a)bwsys.net> wrote:
I figured it out. SER apparently uses strict sub
netting. A /27 is 32 IP's
and 80 is not evenly divisible by 32. I changed it to /28 which is 16 IP's
and since 80/16 = 5 with no remainder it now works. It would be nice if SER
didn't have that limitation but its not that big of a deal because I can
just put an || in the if statement.
For src_ip == ip/mask, ser does (src_ip & mask) == ip.
You would like it to do: (src_ip & mask) == (ip & mask) ?
The change would be trivial, the only question is if it brings any
unexpected matches. In your case x.x.x.80/27 would be equivalent to
x.x.x.64/27.
Andrei