28 Aug
2014
28 Aug
'14
9:37 a.m.
Hi,
From kamailio documentation, the usage of hashtable is
given as :
modparam("htable", "htable", "a=>size=4;")
...
$sht(a=>test) = 1;
$sht(a=>$ci::srcip) = $si;
I get it that in the first statement, a is the hashtable, a new
key-value pair is added to one of its empty bucket (test,1).
What is happening in the second statement?
--
-Cheers
-Arif
28 Aug
28 Aug
11:35 a.m.
New subject: What does "::" operator do in statements related to hashtable?
It's not an operator, actually. :-) It's just a convention. You can call
your keys anything you like (that's grammatically valid).
On 08/28/2014 09:37 AM, aft wrote:
Hi,
From kamailio documentation, the usage of hashtable is given as :
modparam("htable", "htable", "a=>size=4;")
...
$sht(a=>test) = 1;
$sht(a=>$ci::srcip) = $si;
I get it that in the first statement, a is the hashtable, a new
key-value pair is added to one of its empty bucket (test,1).
What is happening in the second statement?
--
Alex Balashov - Principal
Evariste Systems LLC
Tel: +1-678-954-0670
Web: http://www.evaristesys.com/, http://www.alexbalashov.com/
Please be kind to the English language:
http://www.entrepreneur.com/article/232906
12:56 p.m.
New subject: What does "::" operator do in statements related to hashtable?
To give a better visual perspective, practically if you do:
$sht(a=>$ci::srcip) = $si;
for and INVITE request that comes from 1.2.3.4 and has the header:
Call-Id: abcd
Then in the the hash table a is added the pair ('abcd::srcip',
'1.2.3.4').
So, the pseudo variables (the $xy... tokens are evaluated).
Cheers,
Daniel
On 28/08/14 17:35, Alex Balashov wrote:
It's not an operator, actually. :-) It's just
a convention. You can
call your keys anything you like (that's grammatically valid).
On 08/28/2014 09:37 AM, aft wrote:
--
Daniel-Constantin Mierla
http://twitter.com/#!/miconda - http://www.linkedin.com/in/miconda
Next Kamailio Advanced Trainings 2014 - http://www.asipto.com
Sep 22-25, Berlin, Germany ::: Oct 15-17, San Francisco, USA
Hi,
From kamailio documentation, the usage of hashtable is given as :
modparam("htable", "htable", "a=>size=4;")
...
$sht(a=>test) = 1;
$sht(a=>$ci::srcip) = $si;
I get it that in the first statement, a is the hashtable, a new
key-value pair is added to one of its empty bucket (test,1).
What is happening in the second statement?
30 Aug
30 Aug
2:34 a.m.
Thanks for the reply, now i get it
On Thu, Aug 28, 2014 at 10:56 PM, Daniel-Constantin Mierla
<miconda(a)gmail.com> wrote:
To give a better visual perspective, practically if
you do:
$sht(a=>$ci::srcip) = $si;
for and INVITE request that comes from 1.2.3.4 and has the header:
Call-Id: abcd
Then in the the hash table a is added the pair ('abcd::srcip',
'1.2.3.4').
So, the pseudo variables (the $xy... tokens are evaluated).
Cheers,
Daniel
On 28/08/14 17:35, Alex Balashov wrote:
--
-Cheers
-Arif
It's not an operator, actually. :-) It's just a convention. You can call
your keys anything you like (that's grammatically valid).
On 08/28/2014 09:37 AM, aft wrote:
--
Daniel-Constantin Mierla
http://twitter.com/#!/miconda - http://www.linkedin.com/in/miconda
Next Kamailio Advanced Trainings 2014 - http://www.asipto.com
Sep 22-25, Berlin, Germany ::: Oct 15-17, San Francisco, USA
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From kamailio documentation, the usage of hashtable is given as :
modparam("htable", "htable", "a=>size=4;")
...
$sht(a=>test) = 1;
$sht(a=>$ci::srcip) = $si;
I get it that in the first statement, a is the hashtable, a new
key-value pair is added to one of its empty bucket (test,1).
What is happening in the second statement?
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3 comments
3 participants
participants (3)
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aft -
Alex Balashov -
Daniel-Constantin Mierla