Hello,
You can use {uri.host}
<http://www.kamailio.org/wiki/cookbooks/5.0.x/transformations#urihost>
transformation.
Regards,
Szabolcs
2017-03-22 18:23 GMT+01:00 Ali Taher <ataher(a)vanrise.com>om>:
Hello everyone,
I’m trying to get the host part from the contact header in the sip invite
packet.
Following is the contact header format:
Contact: <sip:user_name@192.168.1.1:5060>
What I want as result is 192.168.1.1
I searched among the pseudovairables and found $ct variable which
reference to the body of contact header. (<sip:user_name@192.168.1.1:5060
)
Is there a way to get directly the host (192.168.1.1) without applying
transformation at the level of $ct.
If not what transformation can achieve it.
Thanks in advance.
Regards,
Ali
_______________________________________________
SIP Express Router (SER) and Kamailio (OpenSER) - sr-users mailing list
sr-users(a)lists.sip-router.org
http://lists.sip-router.org/cgi-bin/mailman/listinfo/sr-users