First thinks first: please don't forget to CC the list.. Any information can be for others help. ;)
Well, I would suggest You to make some tests on a command line simulation to be sure what You want to accoplish is even possible. Something like this:
# echo "sip:112345678#@10.10.10.10" | grep -E "^sip:1[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]@"
# echo "sip:112345678#@10.10.10.10" | grep -E "^sip:1[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]@"
# echo "sip:112345678#@10.10.10.10" | grep -E "^sip:1[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"
sip:112345678#@10.10.10.10
# echo "sip:112345678@10.10.10.10" | grep -E "^sip:1[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]@"
sip:112345678@10.10.10.10
# echo "sip:112345678@10.10.10.10" | grep -E "^sip:1[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]@"
sip:112345678@10.10.10.10
#
As OpenSER, and SER as origin, use a regular expression as GREP, You could see that it work like You asked for.
I also run a test in a SER leaving here. I put this code:
} else if (uri=~"^sip:1[0-9]{8}@") { # Test for "1xxxxxxxx" mask numbers
strip(9);
prefix("600");
route(6);
break;
}
And when I call 112345678 from my Softphone, ngrep shows me this forwarded INVITE:
INVITE sip:600@pstn.gw:5060 SIP/2.0..Record-Route: sip:sip.proxy;ftag=1468362515290;lr=on..Via: SIP/2.0/UDP sip.proxy;branch=z9hG4bK90b1.5f
c55385.0..Via: SIP/2.0/UDP client.ip;received=sip.client;rport=1024;branch=z9hG4bKac1bf8060000010f456ef 12a000028cf00000158..From: "Edson -
SJPhone"sip:8201@sip.proxy;tag=1468362515290..To: sip:112345678@sip.proxy..Contact: sip:8201@sip.client..Call-ID: 647DD163-9B1E-45DB-93A2-99
CAC53532B8@client.ip..CSeq: 2 INVITE..Max-Forwards: 16..User-Agent: SJphone/1.61 (SJ Labs)..Content-Length: 217..Content-Type: application/sdp....v=0
..o=- 3373887402 3373887402 IN IP4 sip.client..s=SJphone..c=IN IP4 sip.client..t=0 0..a=setup:active..m=audio 49186 RTP/AVP 4 101..a=rtpmap:4 G723/8000
..a=rtpmap:101 telephone-event/8000..a=fmtp:101 0-11,16..
Which in case is what we are looking for. Identified and translate any 9 digit number, started with '1' to '600'.
Hope that this help You understand all the mechanism.
Edson.
_____
From: raviprakash sunkara [mailto:sunkara.raviprakash.feb14@gmail.com] Sent: quinta-feira, 30 de novembro de 2006 01:24 To: Edson Subject: Re: [Users] regular expression
Hello Edson,
On 11/29/06, Edson 4lists@gmail.com wrote:
Opppsss....
I think that You make a little typo....
Wouldn't the correct be "^sip:1[0-9]{8}@" to match all numbers with 9 digits initiated by an '1' and followed by any combination of digits (from '0' to '9')?
this Regular epression is sip:1[0-9]{8} correct but...... if the number like this ... 112345678# The Red color one must be the digit , not any any special charecter....... According u reg expression ..
So,,, i'm sure ..................... like this it must .......... sip:1{8}[0-9}............
Sorry , if i did any thing mistake......excuse me.........
Edson
_____
From: users-bounces@openser.org [mailto: mailto:users-bounces@openser.org users-bounces@openser.org] On Behalf Of raviprakash sunkara Sent: quarta-feira, 29 de novembro de 2006 11:35 To: Jayesh Nambiar Cc: Users@openser.org Subject: Re: [Users] regular expression
On 11/29/06, Jayesh Nambiar <voip_freak@yahoo.co.in mailto:voip_freak@yahoo.co.in > wrote:
Hi all, Can someone please help me in formulating a regular expression. I have an expression like this: if(uri=~"^sip:1[0-9]*@) This matches numbers like 15552221212, but also matches number like 15552221212#.
when i make it as: if(uri=~"^sip:1[0-9]@*)
Use this if (uri=~"^sip:1{8}[0-9]@" )
Again this matches any special characters after the number.
I just wanted a regular expression that will match only numbers and no alphabets or special characters. Can someone please help me to formulate a regular expression for this.
Thanks in advance.
w/regards, Jayesh
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Edson