Hello,

try:

$(ru{uri.param,user}{s.substr,3,0})

Cheers, Daniel

On 11/13/13 12:13 PM, Oliver Roth wrote:

Hi all

I need to extract a part of the INVITE msg:

INVITE sip:+41796159999@82.197.185.185;user=CSC10824 SIP/2.0

I need

10824

in a avp variable.

Is there a regex function where I can extract this? Or how can this be done?

Something like:

Avp(myCSC) = string after CSC -- length 5

Please be aware, that ip and destination number in the invite can change ...

Otherwise substring would be a solution.

Thanks for help

Oli

---

SIP Express Router (SER) and Kamailio (OpenSER) - sr-users mailing list sr-users@lists.sip-router.org http://lists.sip-router.org/cgi-bin/mailman/listinfo/sr-users

Hi Oli,

On 11/13/2013 06:13 AM, Oliver Roth wrote:

Hi all

I need to extract a part of the INVITE msg:

INVITE sip:+41796159999@82.197.185.185;user=CSC10824 SIP/2.0

I need

10824

in a avp variable.

Hi Oli,

The string you are operating on is called the Request URI, which is exposed by the $ru pseudovariable. The best way to extract it is to use the transformations[1] specifically for extracting URI parameters, which is what 'phone' is:

$avp(user_id) = $(ru{uri.param,user});

If you want '10824' rather than CSC, you can extract a substring:

$avp(user_id) = $(ru{uri.param,user}{s.substr,3,0});

-- Alex

[1] Operations on strings and message parts:

http://www.kamailio.org/wiki/cookbooks/4.0.x/transformations