I am trying to enable RTPPROXY on debian, but it seems RTPProxy is ignoring my arguments...
So, I am launching RTPPROXY using command:
rtpproxy -l _MY_PUBLIC_IP_ -s udp:127.0.0.1 7722 -p /var/run/rtpproxy.pid -R -a -P -r /tmp/rtppath -S /tmp/rtpspool -u rtpproxy rtpproxy
Also tried with:
rtpproxy -l _MY_PUBLIC_IP_ -s udp:127.0.0.1 7722 -u rtpproxy rtpproxy
And when I try to start Kamailio service I am getting error:
0(10562) ERROR: rtpproxy [rtpproxy.c:1681]: send_rtpp_command(): can't send command to a RTP proxy
0(10562) ERROR: rtpproxy [rtpproxy.c:1716]: send_rtpp_command(): proxy does not respond, disable it
0(10562) WARNING: rtpproxy [rtpproxy.c:1573]: rtpp_test(): can't get version of the RTP proxy
0(10562) WARNING: rtpproxy [rtpproxy.c:1610]: rtpp_test(): support for RTP proxy has been disabled temporarily
p.s. I have checked RTPPROXY, and I am sure that it is launched
ps aux | grep rtpproxy
returned me:
root 2770 0.0 0.0 19392 480 ? Ssl 04:59 0:00 /usr/bin/rtpproxy -l _MY_PUBLIC_IP_ -s udp:127.0.0.1 7722 -p /var/run/rtpproxy.pid -R -a -P -r /tmp/rtppath -S /tmp/rtpspool -u rtpproxy rtpproxy
root 2775 0.0 0.0 11740 932 pts/1 S+ 04:59 0:00 grep --color=auto rtp
Which says everything is ok and rtpproxy is running with arguments that I declared
But the problem is, When I check it with:
netstat -tulpn | grep rtpproxy
I am receiving:
udp 0 0 127.0.0.1:22222 0.0.0.0:* 2853/rtpproxy
As you can see rtpproxy is listening on port 22222 and completely ignoring arguments I declared :(
Where and What am I doing wrong?
Sorry for my English and Thanks in advance...
Hi Javohir,
don't worry, your english is fine. Can you send us the parameters you have set for rtpproxy in your kamailio cfg? You should find something like this:
modparam("rtpproxy", "rtpproxy_sock", "udp:localhost:22222")
Make sure it matches the configuration of the RTPProxy.
Thanks, Carsten
2015-12-09 11:32 GMT+01:00 Javohir Maxmarajabov javokhirbek14@gmail.com:
I am trying to enable RTPPROXY on debian, but it seems RTPProxy is ignoring my arguments...
So, I am launching RTPPROXY using command:
rtpproxy -l _MY_PUBLIC_IP_ -s udp:127.0.0.1 7722 -p /var/run/rtpproxy.pid -R -a -P -r /tmp/rtppath -S /tmp/rtpspool -u rtpproxy rtpproxy
Also tried with:
rtpproxy -l _MY_PUBLIC_IP_ -s udp:127.0.0.1 7722 -u rtpproxy rtpproxy
And when I try to start Kamailio service I am getting error:
0(10562) ERROR: rtpproxy [rtpproxy.c:1681]: send_rtpp_command(): can't send command to a RTP proxy
0(10562) ERROR: rtpproxy [rtpproxy.c:1716]: send_rtpp_command(): proxy does not respond, disable it
0(10562) WARNING: rtpproxy [rtpproxy.c:1573]: rtpp_test(): can't get version of the RTP proxy
0(10562) WARNING: rtpproxy [rtpproxy.c:1610]: rtpp_test(): support for RTP proxy has been disabled temporarily
p.s. I have checked RTPPROXY, and I am sure that it is launched
ps aux | grep rtpproxy
returned me:
root 2770 0.0 0.0 19392 480 ? Ssl 04:59 0:00 /usr/bin/rtpproxy -l _MY_PUBLIC_IP_ -s udp:127.0.0.1 7722 -p /var/run/rtpproxy.pid -R -a -P -r /tmp/rtppath -S /tmp/rtpspool -u rtpproxy rtpproxy
root 2775 0.0 0.0 11740 932 pts/1 S+ 04:59 0:00 grep --color=auto rtp
Which says everything is ok and rtpproxy is running with arguments that I declared
But the problem is, When I check it with:
netstat -tulpn | grep rtpproxy
I am receiving:
udp 0 0 127.0.0.1:22222 0.0.0.0:* 2853/rtpproxy
As you can see rtpproxy is listening on port 22222 and completely ignoring arguments I declared :(
Where and What am I doing wrong?
Sorry for my English and Thanks in advance...
-- Javokhir M.M. ________________________________________________
Disclaimer: The information in this e-mail is confidential. If you are not addressed recipient then please return and delete this e-mail from your system. Unauthorised use of or disclose the contents of this e-mail may be unlawful.
SIP Express Router (SER) and Kamailio (OpenSER) - sr-users mailing list sr-users@lists.sip-router.org http://lists.sip-router.org/cgi-bin/mailman/listinfo/sr-users