Hi all, I have the following scenario: U1 (caller) ---> P1 (192.168.0.245, kamailio 4.3, loose-router) ----> P2 ----> (192.168.0.101, strict router) ----> .... ----> U2 (called)
When U2 answers the call, at P1 arrives the 200 OK with: Record-Route: sip:0000000011@192.168.0.101;transport=udp;pgw-call=call-28d2e Record-Route: sip:192.168.0.245;lr=on
The problem is that the ACK from U1 is forwarded from kamailio to P2, as if P2 is a loose router. P2 drops the ACK message.
From kamailio logs I see: Jul 14 10:07:44 P1 /usr/sbin/kamailio[15908]: DEBUG: rr [loose.c:88]: is_preloaded(): is_preloaded: No Jul 14 10:07:44 P1 /usr/sbin/kamailio[15908]: DEBUG: rr [loose.c:783]: after_loose(): Topmost route URI: 'sip:192.168.0.245;lr=on' is me Jul 14 10:07:44 P1 /usr/sbin/kamailio[15908]: DEBUG: rr [loose.c:869]: after_loose(): URI to be processed: 'sip:0000000011@192.168.0.101;transport=udp;pgw-call=call-289ce' Jul 14 10:07:44 P1 /usr/sbin/kamailio[15908]: DEBUG: rr [loose.c:878]: after_loose(): Next URI is a loose router
Why after_loose function considers the next URI a loose router? The Route HF in the ACK with the URI of the next hop does not contain ;lr . It seems that the function is_strict fails detecting the strict router.
Thanks.
Regards.
Antonio