11 Jun
2013
11 Jun
'13
1:54 p.m.
Mino,
Something like this should probably work:
$var(x) = "1,2,3,4";
$var(i) = 0;
while(defined $(var(x){s.select,$var(i),,})) { ...
$var(i) = $var(i) + 1; }
If the 'defined' operator always results 'true' on the results of this transformation, then alternately this:
while($(var(x){s.select,$var(i),,}{s.len}) > 0)
-- Alex
--
Alex Balashov - Principal
Evariste Systems LLC
235 E Ponce de Leon Ave
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Tel: +1-678-954-0670
Web: http://www.evaristesys.com/, http://www.alexbalashov.com/