26 Jun
2016
26 Jun
'16
3:06 a.m.
I knew there had to be a better option! Thanks Federico :)
Best regards,
Joel.
----- Original Message -----
From: "Federico Cabiddu"
<federico.cabiddu(a)gmail.com>
To: "Kamailio (SER) - Users Mailing List"
<sr-users(a)lists.sip-router.org>
Sent: Friday, June 24, 2016 11:45:50 PM
Subject: Re: [SR-Users] Parsing diversion headers correctly
Hi Joel,
to the extract the username part of the last Diversion header you could modify
your last example like this:
$(hdr(Diversion)[-1]{nameaddr.uri}{uri.user})
Regards,
Federico
On Sat, Jun 25, 2016 at 3:23 AM, Joel Serrano |
VOZELIA < joel(a)vozelia.com >
wrote:
> Hi,
> If you receive an INVITE with 2 diversion headers
such as (in this order):
> Diversion:
<sip:9975@X.X.X.X:5060>;privacy=off;screen=no; reason=user-busy;
> counter=1
> Diversion: <sip:1234567890@Z.Z.Z.Z:5060>;privacy=off;screen=no;
reason=unknown;
> counter=1
> How is a nice way of extracting the user part from
the URI of the last one? (in
> this case: 1234567890)
> Problems I have found:
> $(di{uri.user}) ---> Give mes the user part of
the URI of the first header, in
> this case: 9975
> Is there a way to tell $di to get its value from
the last header instead of the
> first one?
> This example works:
> $(hdr(Diversion)[-1]{ param.name
,0}{s.strip,1}{s.striptail,1}{uri.user})
> But I think it is very hacky...
> Any better approach anyone can suggest me?
> Thanks in advance.
> Best regards,
> Joel.
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