remove_hf('Contact') and then append_hf($var(contact)) should work. What was the problem you were having? Were you using it in a branch route?
John
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On Thu, Nov 2, 2017 at 6:40 PM, Diego Nadares dnadares@gmail.com wrote:
Hi again,
I found a work around . Modifying $ru changes de first contact uri.
if($var(routing)=~"redirect"){ jansson_get("contacts_len", "$var(evmsg)", "$var(contacts_len)"); xlog("L_INFO", "Contacts len $var(contacts_len)"); $var(i) = 0;
*$var(first) = 0;* while ($var(i) < $var(contacts_len)){ jansson_get("contacts[$var(i)]", "$var(evmsg)","$var(contact)"); if ($var(first) == 0){ * $ru = $var(contact);* * $var(first) = 1;* } #Appending anyway because of the q param append_branch($var(contact), "0.5"); $var(i) = $var(i) + 1; } send_reply("302", "Moved Temporarily"); exit; }
Contact: *<1111@188.111.111.112 sip%3A1111@188.111.111.112>*, < sip:1111@188.111.111.112>;q=0.5, sip:1111@188.111.111.112;q=0.5
I think this is not the better way. Any suggestion will be very appreciated.
Thanks again.
Diego
2017-11-02 18:11 GMT-03:00 Diego Nadares dnadares@gmail.com:
Hi Guys,
I'm generating a 302 reply from kamailio. In this 302 I append new branches with new contacts.
if($var(routing)=~"redirect"){ jansson_get("contacts_len", "$var(evmsg)", "$var(contacts_len)"); xlog("L_INFO", "Contacts len $var(contacts_len)"); $var(i) = 0; while ($var(i) < $var(contacts_len)){ jansson_get("contacts[$var(i)]", "$var(evmsg)", "$var(contact)"); append_branch($var(contact), "0.5"); $var(i) = $var(i) + 1; } send_reply("302", "Moved Temporarily"); exit; }
The problem i'm facing is that I can't delete the original contact *<sip:1111@188.111.111.111:5060 http://sip:1111@188.111.111.111:5060>*
The resulting conctact:
Contact: *<sip:1111@188.111.111.111:5060 http://sip:1111@188.111.111.111:5060>*, sip:1111@188.111.111.112;q=0.5, sip:1111@188.111.111.112;q=0.5
I all ready tried with remove_hf('Contact') and adding the new ones after that but it doesn't worke either.
The problem is that one gw takes the first contact over and over again and never the other two.
Thanks in advance.
Diego.
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