11 Jan
2007
11 Jan
'07
6:10 p.m.
I get the follwing response from openserctl show ul
~~~Contact(0x284a6880)~~~ domain : 'location' aor : '1020111' Contact : 'sip:1020111@192.168.0.198:5060' Expires : 3592 q : Call-ID : '4ef617d2-8e70ad17@192.168.0.198' CSeq : 4249 User-Agent: 'Linksys/SPA3102-5.1.5(GWa)' received : 'sip:67.188.231.188:62292' Path : '' State : CS_DIRTY Flags : 0 Sock : 66.224.20.35:5060 (0x8123fb0) Methods : 5183 next : 0x0 prev : 0x0 ~~~/Contact~~~~
Can anybody tell me the meaning of the CS_DIRTY state reply?
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