Thanks John for the Reply.
So if i understand properly : group 1 is here <sip:anonymous@ group 2 is empty group 3 is ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD
the previous expression is working for IPv4.
Now for IPv6
Input : From: sip:anonymous@ [2008:abcd:1234:2260:208:5dff:fe93:5b65];tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092 subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig'); Output : From: sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb];tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092 //what is going wrong here?
Here group 1 is <sip:anonymous@ group 2 is empty group 3 is ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092
what mistake am i making for IPv6 ? if you see the output.
Regards, Mahesh.b
On Mon, Jul 2, 2018 at 6:54 PM John Petrini jpetrini@coredial.com wrote:
They are references to groups in the regex match. The groups are in parenthesis. Whatever is matched by group 1 and 3 will be included in the substitution.
https://regexr.com/ and https://regex101.com/ are both good sites for building and explaining regexes. _______________________________________________ Kamailio (SER) - Users Mailing List sr-users@lists.kamailio.org https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users