[Kamailio-Users] openser and asterisk auth problem.

[LetMeKnow]

Hi,
in asterisk sip.conf file ...

[openser]
type = friend
host=ip_address_of_open
insecure = very
username=dummy_name
proxy= host
outbound_proxy=host
nat = yes;
canreinvnit =no;

And In Asterisk CTL > show sip peers
You will see the openser peer is registered....


And See openSER debug whether Option Header and Signaling Happing properly
or not.
In openSER.cfg check asterisk ip is restricting or not ?


Thanks &Regards
Ravi Prakash Sunkara
VoIP Architect & JAVA-SIP Developer
+91-9999882776


2008/12/18 BERGANZ François <francois at acropolistelecom.net>

>
> I want to authenticate in openser some users which are in asterisk conf (to
> do load balancing with another asterisk).
> If I delete the user from the asterisk config and insecure=invite for the
> openser, asterisk accept the call, but, I want that asterisk see that it is
> that user which is doing the call.
>
>
> Cordialement,
> BERGANZ François
>
>
> http://www.acropolistelecom.net
>  Pensez à l'Environnement, n'imprimez ce mail que si nécessaire.
>
>
> -----Message d'origine-----
> De : Andrew V.Statsenko [mailto:alter at siptalk.ru]
> Envoyé : jeudi 18 décembre 2008 11:00
> À : BERGANZ François
> Objet : ***SPAM*** Re: [Kamailio-Users] openser and asterisk auth problem.
>
> В Чтв, 18/12/2008 в 10:31 +0100, BERGANZ François пишет:
> > -----I have that error:
>
> > <--- SIP read from UDP://192.168.1.156:5060 --->
> > INVITE sip:33662971130 at 192.168.1.156 <sip%3A33662971130 at 192.168.1.156>SIP/2.0
> > Record-Route: <sip:192.168.1.156;lr=on;ftag=0c46027a>
> > Via: SIP/2.0/UDP 192.168.1.156;branch=z9hG4bK20d2.de427962.0
> > Via: SIP/2.0/UDP 192.168.1.60:43490
> ;branch=z9hG4bK-d8754z-c15d2350d0742a11-1---d8754z-;rport=43490
> > Max-Forwards: 70
> > Contact: <sip:6833211245 at 192.168.1.60:43490>
> > To: "33662971130"<sip:33662971130 at 192.168.1.156<sip%3A33662971130 at 192.168.1.156>
> >
> > From: "6833211245"<sip:6833211245 at 192.168.1.156<sip%3A6833211245 at 192.168.1.156>
> >;tag=0c46027a
> > Call-ID: YTkxOWU5MGJjZjJhMWFmODZhMzZkMTU1YzUzYjUyMTc.
> > CSeq: 2 INVITE
> > Allow: INVITE, ACK, CANCEL, OPTIONS, BYE, REFER, NOTIFY, MESSAGE,
> SUBSCRIBE, INFO
> > Content-Type: application/sdp
> > User-Agent: X-Lite release 1100l stamp 47546
> > Content-Length: 231
> [..]
>
>
>
> > <------------->
> > --- (14 headers 10 lines) ---
> > Sending to 192.168.1.156 : 5060 (no NAT)
> > Using INVITE request as basis request -
> YTkxOWU5MGJjZjJhMWFmODZhMzZkMTU1YzUzYjUyMTc.
> > Found user '6833211245' for '6833211245'
>
> This is the key trouble in your configuration: Asterisk trying to
> authenticate this call as call from _user_ (INVITE->401->INVITE+auth),
> but not as _peer_.
>
>
> Will you describe us where you want to authenticate you users :
>
> - at the OpenSER frontend (BTW, I don't see auth headers in first
> INVITE)
> - or in the Asterisk backend ?
>
>
> Which service logic you are building ?
>
> --
> WBR,
> Alter
>
>
>
>
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>
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