[Serusers] Question on How Start MEDIAPROXY.

[Ricardo Martinez]

Hello.
	For those who have the same problem i have found a "work-around"
solution.

In the pyhton file, for example mediaproxy.py, there is a #! at the
beggining of the file with the route to the bin.  You have to change this
for :

[prompt %]which pyhton2.3
/usr/local/bin/python2.3  

this path is replaced in the mediaproxy.py file : 

#!/usr/local/bin/python2.3

'''Provides a RTP Proxy server to be used in conjunction with SER's
mediaproxy
module. MediaProxy stands in between the 2 SIP clients participating in a
VoIP
conversation and forwards the RTP and RTCP streams between them, allowing
the SIP clients to work behind NAT without special settings on their behalf.
MediaProxy must have a public IP.
'''
....

at least that works for me ! 
Goos Luck.

Ricardo Javier Martinez Ogalde
Ingeniero de Desarrollo
VOISS NET S.A.
Cisco Certified Network Associate
*   :  (56 2) 240 81 96
*    :  (56 2) 245 74 95
*   :  rmartinez at redvoiss.net


> -----Mensaje original-----
> De: Ricardo Martinez [mailto:rmartinez at redvoiss.net]
> Enviado el: Martes, 08 de Febrero de 2005 13:03
> Para: 'serusers at lists.iptel.org'
> Asunto: [Serusers] Question on How Start MEDIAPROXY.
> 
> 
> Hello list.
> 	I have a question on How to Start Mediaproxy server.  
> When i start
> mediaproxy from the console i obtain the following error:
> 
> [root at sipproxy mediaproxy]# ./mediaproxy.py                  
>   File "./mediaproxy.py", line 84
>     print >>sys.stderr, "Mediaproxy error: %s. Exiting." % why
>            ^
> SyntaxError: invalid syntax
> 
> however i have installed Python2.3 
> [root at sipproxy mediaproxy]# python
> python     python1.5  python2    python2.2  python2.3  
> 
> When i start mediaproxy with the next lines it works ok : 
> 
> [root at sipproxy mediaproxy]# python2.3 mediaproxy.py
> 
> So i made a test and i started mediaproxy with the original python.
> 
> [root at sipproxy mediaproxy]# python mediaproxy.py     
>   File "mediaproxy.py", line 84
>     print >>sys.stderr, "Mediaproxy error: %s. Exiting." % why
>            ^
> SyntaxError: invalid syntax
> 
> And i obtained the same initial error.
> My question is : Is there a way to force mediaproxy to start with the
> pyhton2.3? and therefore make mediaproxy start with 
> %./mediaproxy.py and
> pyhton2.3
> 
> Hope that someone can help me here.
> 
> Thanks in advance,
> 
> Ricardo Martinez.-
> 
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