[Kamailio-Users] Quick REGEX to match Private IP

[Uriel Rozenbaum]

Done,

I had a lot of errors so I'll just show the final version that works OK.

 =~ "192\.168\.([0-9]{1,3})\.([0-9]{1,3})

The only drawback is that I could pass as valid 192.168.999.999 but as these
IPs come from a DNS query, I assume they'll be fine.

Cheers,
Uriel

On Fri, Mar 26, 2010 at 11:29 AM, Uriel Rozenbaum <uriel.rozenbaum at gmail.com
> wrote:

> Hi Alex,
>
> Actually what I'm trying to do is check the IPs on a request on a
> Kamailio+RTPProxy acting as border of our network.
>
> So I have the ingress IP and egress IP and need to check if I have to
> bridge ii, ei, ie or ee.
> I managed to obtain all IPs in AVPs, but now I have to check if they are
> public or private.
>
> So far our network uses only 192.168.x.x class for private servers.
>
> Thanks for the quick reply
> Uriel
>
>
> On Fri, Mar 26, 2010 at 10:56 AM, Alex Balashov <abalashov at evaristesys.com
> > wrote:
>
>> 172.16.0.0/12 does not line up on octet boundaries.  You will need to do
>> something other than a regular expression.  Fortunately, 'src_ip' is a
>> composite that supports comparisons against subnets in shorthand CIDR
>> notation.
>>
>> It might also be that whatever you are trying to accomplish can be done
>> better some other way, but since you did not pose the question in terms of
>> the objective, I cannot speak to that.
>>
>> --
>> Sent from mobile device
>>
>>
>> On Mar 26, 2010, at 9:46 AM, Uriel Rozenbaum <uriel.rozenbaum at gmail.com>
>> wrote:
>>
>>  Hi guys,
>>>
>>> Does anyone have a REGEX syntax to match a private IP on the 192.168.x.x
>>> range?
>>>
>>> I'm trying with:
>>> if($avp(s:ip_origen)=~"192.168(\.([1]?\d{1,2}|2[0-4]{1}\d{1}|25[0-5]{1})){2}"
>>> )
>>>
>>> But all IPs pass as private, even public ones.
>>>
>>> Thanks!
>>> Uriel
>>> _______________________________________________
>>> Kamailio (OpenSER) - Users mailing list
>>> Users at lists.kamailio.org
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>>>
>>
>
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