[Kamailio-Users] Quick RTPproxy question
Klaus Darilion
klaus.mailinglists at pernau.at
Mon Mar 22 19:00:47 CET 2010
Am 22.03.2010 14:13, schrieb Uriel Rozenbaum:
> Hey, thanks for both replies from Daniel and Klaus.
>
> Klaus, will this work on kamailio 1.5.3 the same way?
AFAIK: yes
> Daniel, sorry I misstyped. The first flags should be ocfaei and the
> second ones ocfaie.
>
> What I meant with the question is:
> I receive an invite from public IP; I call force_rtp_proxy("ocfaei");
> Then I receive the reply (lets say 183 or 200) and I call
> force_rtp_proxy("ocfaie");
>
> Is this right?
No, read the description:
'i' corresponds to rtpproxy's first interface
'e' corresponds to rtpproxy's second interface.
so you should use: rtpproxy -l PRIVATE_IP/PUBLIC_IP
Then, the force_rtp_proxy calls should work.
Further: if the client in the public network is behind NAT you should
not use the 'a' flag.
regards
klaus
>
> Thanks in advance,
> Uriel
>
> On Mon, Mar 22, 2010 at 6:20 AM, Klaus Darilion
> <klaus.mailinglists at pernau.at <mailto:klaus.mailinglists at pernau.at>> wrote:
>
> Recently I have rewritten the documentation about using the e/i
> flag. See
>
> http://sip-router.org/docbook/sip-router/branch/master/modules_k/nathelper/nathelper.html#id2907572
>
> regards
> klaus
>
> Am 19.03.2010 22:12, schrieb Uriel Rozenbaum:
>
> Hi guys,
>
> I have some easy doubt about nathelper functions using RTPProxy.
>
> I'm trying to bridge from an external IP to an internal IP.
> The start-line for rtpproxy is: rtpproxy -l PUBLIC_IP/PRIVATE_IP -s
> udp:127.0.0.1:7999 <http://127.0.0.1:7999>
> <http://127.0.0.1:7999> -F
>
> It starts OK and I see it when kamailio starts.
>
> I'm going to use something like Daniel showed on some other mail:
>
> if(dst_ip==private)
> force_rtp_proxy("ocfaei");
> else
> force_rtp_proxy("ocfaei");
>
> if i have the invite from a public IP to someone in private on the
> request I'll run
> force_rtp_proxy("ocfaei");
> then the reply will be from private to public... should I run
> "force_rtp_proxy("ocfaei");"? or should it be the same?
>
> As allways, thanks for your help.
>
> Kind regards,
> Uriel
>
>
>
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