[SR-Users] strange conditional "if ($au!=$tU)" with previous exit
PICCORO McKAY Lenz
mckaygerhard at gmail.com
Tue Oct 29 16:35:45 CET 2019
i have this in asterisk integration how to, and i noted the "exit"
before the "if($au!=$tU)" .. i dont understan the conditional and the
exit there!
please can someon xplain me that!?
# authenticate the REGISTER requests (uncomment to enable auth)
#!ifdef WITH_ASTERISK
if (!www_authorize("$td", "sipusers"))
#!else
if (!www_authorize("$td", "subscriber"))
#!endif
{
www_challenge("$td", "0");
exit;
}
if ($au!=$tU)
{
sl_send_reply("403","Forbidden auth ID");
exit;
}
i investigate at the kamailio cgf documentation and there's no clear
topic related!
http://www.kamailio.org/wiki/cookbooks/5.2.x/pseudovariables#tu_-_to_uri
Lenz McKAY Gerardo (PICCORO)
http://qgqlochekone.blogspot.com
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