[SR-Users] XAVP question

[Daniel-Constantin Mierla]

Hello,

whenever you want to add one xavp, you must not provide the index. Try:

$xavp(arr=>foo1) = 'bar1';
$xavp(arr[0]=>foo2) = 'bar2';
$xavp(arr=>foo1) = 'bar3';
$xavp(arr[0]=>foo2) = 'bar4';

Note that is still adding as a stack, like for avp. But when you provide 
an index, it is expecting to exist and overwritte if all indexes are 
provided.

Cheers,
Daniel

On 27/12/13 09:34, Kelvin Chua wrote:
> i'm trying to create an array (similar to sql_xquery result) using xavp,
> i tried the ff:
>
> $xavp(arr[0]=>foo1) = 'bar1';
> $xavp(arr[0]=>foo2) = 'bar2';
> $xavp(arr[1]=>foo1) = 'bar3';
> $xavp(arr[1]=>foo2) = 'bar4';
>
> this does not work.
>
> Kelvin Chua
>
>
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-- 
Daniel-Constantin Mierla - http://www.asipto.com
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