[sr-dev] [kamailio/kamailio] uri.param and param.value error when last character is delimiter (#1991)
notifications at github.com
Tue Jun 25 17:31:09 CEST 2019
I receive such URIs from Asterisk 16.3 . This extra delimiter at the end seems to appear when Asterisk has stored contact URIs which are bigger than the db field. My fullcontact field length was 256 bytes in the Asterisk db, now I increased to 512 bytes and the problem went away.
Yes, I chop off the last delimiter in Kamailio now. That prevents the problem.
Thanks for your hints.
> On 25 Jun 2019, at 18:05, Daniel-Constantin Mierla <notifications at github.com> wrote:
> From where did you get such URI? Because, afaik, by specs/RFC grammar, the uri must not be terminated by ; -- the last param value must be left without ;.
> I haven't implemented the parser for uri+params, but that's what I understood from the developer long time ago. I know that for some some modparams that use the uri-params parser, I had to check if the last char is ; and skip it when passing the value to the parser to avoid loosing the checks of the parser to break specs requirements.
> The solution right now is to check the last char in such value and skip it using other string transformations such as s.substr.
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