Thanks John for the Reply.

So if i understand properly :

group 1 is here  <sip:anonymous@

group 2 is empty

group 3 is  ;tag=41008079_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_78DD

the previous expression is working for IPv4.

Now for IPv6

Input         :           From: <sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b65]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092

subst('/^From:(.*)[2008:abcd:1234:2260:208:5dff:fe93:5b65](.*)>(.*)/From:\1[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>\3/ig');

Output      :           From: <sip:anonymous@[2008:abcd:1234:2260:208:5dff:fe93:5b6[2008:abcd:1234:2260:20c:29ff:fe9a:b9cb]>;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092    //what is going wrong here?

Here 

group 1 is   <sip:anonymous@

group 2 is empty

group 3 is  ;tag=42006C96_nab_FFFF_isp_FFFF_cco_FFFF_igo_FFFF_mgt_8092

what mistake am i making for IPv6 ? if you see the output.

Regards,

Mahesh.b

On Mon, Jul 2, 2018 at 6:54 PM John Petrini <jpetrini@coredial.com> wrote:

They are references to groups in the regex match. The groups are in parenthesis. Whatever is matched by group 1 and 3 will be included in the substitution.

https://regexr.com/ and https://regex101.com/ are both good sites for building and explaining regexes.

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