> On Apr 26, 2024, at 5:17 PM, Pavan Kumar via sr-users <sr-users@lists.kamailio.org> wrote:
>
> Hello everyone,
>
> While going through the WebRTC example configuration (cfg) to better understand and implement it in my setup, I came across a potential issue in the code block. The code in question can be found at this link: https://github.com/kamailio/kamailio/blob/465994de2859c7863b4cef8457be0a207f15c932/misc/examples/webrtc/websocket.cfg#L253
>
> In the code, there is an "if else" block, "if(loose_route())" that seems to be incorrect. It appears that the "if" block will always evaluate to true, given that "loose_route" never returns 0. According to the documentation, the return values of "loose_route" are specified as 1, 2, -1, -2, -3.
>
> Therefore, it seems the "if" block is unnecessary, and the "else" block will never be executed. Could someone please confirm this observation and, if accurate, suggest a correction for the code?
>
> Thank you for your attention to this matter.
>
> Best regards,
> Pavan Kumar


1,2 would be a true response.
-1,-2,-3 would be a false response.

https://www.kamailio.org/docs/modules/stable/modules/rr.html#rr.f.loose_route

" If there is no Route: header, the function returns FALSE and routing should be done with normal lookup functions. If a Route: header is found, the function returns 1 and behaves as described in section 16.12 of RFC 3261. There is only one exception: If the request is out-of-dialog (no to-tag) and there is only one Route: header indicating the local proxy, then the Route: header is removed and the function returns FALSE."


Regards,

Fred Posner
p: +1 (352) 664-3733
https://qxork.com



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