On 30/09/14 11:46, Julia Boudniatsky wrote:

$(tu{uri.uparam,cic}) gets ERROR wrong format,

$(tu{uri.uparam}) return : phone

So, uparam return the value of parameter "user" .

Right, I forgot what I implemented and misread the docs.

You should add a transformation to return the user parameters.

I solved a problem by usage $(tu{param.value,cic,;})

Be careful not to have cic as last parameter before @.

Might be safer to use:

$(tu{s.select,0,@}{param.value,cic})

Cheers,
Daniel

BR

Julia
On Tue, Sep 30, 2014 at 12:09 PM, Daniel-Constantin Mierla <miconda@gmail.com> wrote:
Hello,

On 30/09/14 10:41, Julia Boudniatsky wrote:

Hello,

Some Uri transformations stopped working after upgrade  from 3.3 to 4.1.6.

To: <sip:01412127775678;cic=012;csel=noind@10.25.153.150:5060;user=phone>

In v3.3

$tu({uri.params})          return:  cic=012;csel=noind

$tu({uri.param,cic}) return:        012

In v4.1.6

$tu({uri.params})     return :  user=phone

$tu({uri.param,cic}) return :

looks like this is happening as a fix, as the cic is an username parameter, not a uri parameter.

You should use {uri.uparam,cic}:

http://www.kamailio.org/wiki/cookbooks/devel/transformations#uriuparam

Cheers,
Daniel

-- Daniel-Constantin Mierla http://twitter.com/#!/miconda - http://www.linkedin.com/in/miconda
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