David,
My problem is actually rtpproxy. I have to use a particular IP as the source address for RTP sending.
Best regards,
Leonid Fainshtein
Xorcom Ltd


On Wed, Apr 22, 2020 at 9:51 PM David Villasmil <david.villasmil.work@gmail.com> wrote:
Hello,

In terms of private/public IP addresses,in kamailio you would need to "advertise" the public IP address, such that:

listen=udp:192.168.0.10:5060 ADVERTISE 123.123.123.123:5060

So kamailio, when sending out, utilises that public (advertise) IP address as its own address.
I don't know of any mechanism that allows you to set two different public IP addresses as advertised addresses.

You _can_ receive  from multiple public IPs by setting multiple aliases, like:

alias=123.123.123.123:5060
alias=213.213.213.213:5060

and kamailio would process them as its own IPs.
But when sending out, it will use the ADVERTISED address.

So the correct thing to do is to have multiple private address mapped one-to-one to public ip address, i.e.:

listen=udp:192.168.0.10:5060 ADVERTISE 123.123.123.123:5060
listen=udp:192.168.0.20:5060 ADVERTISE 213.213.213.213:5060

This _would_ work properly.

Regards,

David Villasmil
phone: +34669448337


On Wed, Apr 22, 2020 at 7:04 PM Leonid Fainshtein <leonid.fainshtein@xorcom.com> wrote:
Can you elaborate a little? I didn't understand you.
Best regards,
Leonid 



On Wed, Apr 22, 2020 at 6:53 PM David Villasmil <david.villasmil.work@gmail.com> wrote:
I think mapping IPs is a one-to-one relationship 

On Wed, 22 Apr 2020 at 16:18, Leonid Fainshtein <leonid.fainshtein@xorcom.com> wrote:
Hi,
My server has several external IP interfaces and one internal interface. For some calls I would like to handle RTP via Ext1<->Int interfaces and for other calls: via Ext2<->Int.
In order to achieve this,  I don't define the '-l' rtpproxy parameter, and depending on the call, I set the required IP address as a parameter of rtpproxy_manage(). 
I didn't succeed to get the desired result.
On my testbed, I have the following interfaces:
Ext1: 192.168.0.31
Ext2: 192.168.0.32
Int:     10.159.65.1

When I try to create Ext2<->Int (192.168.0.32<-> 10.159.65.1), the packets that accepted on the internal interface are sent out from the Ext1(192.168.0.31) instead of Ext2 (192.168.0.32). It looks like the decision about the source address is made based on the IP routing table information (?).
Also, I would like to have an advertised address for at least one external interface.

Is it achievable with just one instance of rtpproxy? Or, it is necessary to run two rtpproxies in the bridged mode wit configured advertize addresses?

Thank you in advance,
Leonid

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Regards,

David Villasmil
phone: +34669448337
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