<div dir="ltr"><br><br><div class="gmail_quote">On Sun, Oct 12, 2008 at 3:52 PM, Alex Balashov <span dir="ltr"><<a href="mailto:abalashov@evaristesys.com">abalashov@evaristesys.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
Yep. What Iñaki said.<br>
<br>
In any sort of programming language-like runtime environment, which<br>
Kamailio script is, when you evaluate two actual statements in a<br>
disjunction rather than values holding return codes, those statements<br>
get executed right then and there.<br>
<br>
So, whether the first t_relay() ran successfully or not, the second one<br>
will be executed. This won't work unless you branch.<br>
<div class="Ih2E3d"><br>
Iñaki Baz Castillo wrote:<br>
<br>
> El Domingo, 12 de Octubre de 2008, Asim Riaz escribió:<br>
>> if(!t_relay("udp:third_proxy_1:5060") ||<br>
>> !t_relay("udp:third_proxy_2:5060")) {<br>
><br>
> I think that this is not valid, you can not check the result of sending the<br>
> request to both destinations.<br>
><br>
> If the first condition is false (!t_relay("udp:third_proxy_1:5060") this means<br>
> that a transaction has been correctly created. But after that you do a new<br>
> comparision:<br>
> !t_relay("udp:third_proxy_2:5060")<br>
> The transaction was already created in the first t_realy so you are trying to<br>
> do it again in a new t_relay, that is illegal.<br>
><br>
><br>
so then what is the posibility to send calls the first proxy if thats fail route to another one and so on ?</div></blockquote><div><br>Thanks<br>Asim Riaz <br></div><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div class="Ih2E3d"><br>
<br>
--<br>
</div><font color="#888888">Alex Balashov<br>
Evariste Systems<br>
Web : <a href="http://www.evaristesys.com/" target="_blank">http://www.evaristesys.com/</a><br>
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Direct : (+1) (678) 954-0671<br>
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