<p>According to <a href="https://www.kamailio.org/wiki/cookbooks/5.1.x/transformations" rel="nofollow">https://www.kamailio.org/wiki/cookbooks/5.1.x/transformations</a> (and I'm using 5.1), I should be able to do something like <code>$var(num)=$(fU{s.substr,-1,10})</code> and <code>$var(num)</code> should be <code>123456789</code> if <code>$fU</code> is <code>0123456789</code> (only the last 10 characters are displayed).  However, <code>$var(num)</code> ends up with only the last character of the substring, in this case, <code>9</code>.</p>

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